angelliu11 angelliu11

10-08-2017
Mathematics

contestada

Find 3 consecutive positive integers such that the product of the first and third integers is 48. Solve algebraically.

Respuesta :

Аноним Аноним

10-08-2017

let integers be x , x+1 and x+2

x(x + 2) = 48

x^2 + 2x - 48 = 0

(x + 8)(x - 6) = 0

x = 6 ( because the integrs are positive

so the 3 numbers are 6,7 and 8.

Answer Link

Otras preguntas

Where are metals and minerals most often found?

9/10-1/3-1/5 find the fraction

Should the government classify Bitcoin as a legal currency? (I need the pros side. I have a debate on this)

What did puritans think about bishops and priests

As Venus revolves around the sun, it travels at a speed of approximately 22 miles per second. Convert this speed to kilometers per second. At this speed, how

since improper fractions always need to be converted, how do I convert 7/3 into a mixed fraction?

Absorbance readings are taken for five standard ferrous (ii) thiocyanate solutions and a beer’s law plot is created with the equation: y = 3.2975x + 0.0021. a f

Rewrite 18/24 with a denominator of 6

The variables xp and yp have both been declared as pointers to integers, and have been assigned values. write the code to exchange the two integers (so that aft

What does "CPU" stand for?

good job