aleinamaldonado aleinamaldonado
  • 05-04-2024
  • Mathematics
contestada

What is the axis of symmetry for the quadratic equation below
f(x)=3x+48x+20

Respuesta :

luclaporte2
luclaporte2 luclaporte2
  • 05-04-2024

Answer:

x = -8

Step-by-step explanation:

The axis of symmetry can be found using the formula:

x = -b/2a

This applies to the standard form equation f(x) = ax^2+bx+c.

Since f(x) = 3x² + 48x + 20; a = 3, b = 48, and c = 20.

Substituting the variables we get:

x = -(48) / 2(3)

x = -48 / 6

x = -8

Therefore, the axis of symmetry is located at x = -8

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