Respuesta :

olumideolawoyin

Answer:

10√2 ms^-1

Explanation:

Horizontal component of its velocity = 20 × cos 45° = 20/√2 by rationalization

=

[tex] \frac{20}{ \sqrt{2}} \times \frac{ \sqrt{2} }{ \sqrt{2} } = \: \frac{20 \sqrt{2} }{2} = 10 \sqrt{2} {ms}^{ - 1} [/tex]

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