ttt43
ttt43
06-09-2017
Mathematics
contestada
I do not know how to do this
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WojtekR
WojtekR
06-09-2017
[tex]g=\dfrac{x-c}{x}\quad|\cdot x\\\\\\gx=x-c\\\\gx-x=-c\\\\x(g-1)=-c\quad|:(g-1)\\\\\boxed{x=-\frac{c}{g-1}=\frac{c}{1-g}}[/tex]
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