Respuesta :

coolstick
Since f(g(x)) essentially means that we plug f(x) into what g(x) already is (e.g. if g(x) is x^2 and f(x) is x+1, then f(g(x)) is x^2+1). If g(x) is 2/x^2 (the first part of y) and f(x) is x+3, in f(g(x)) g(x) essentially replaces x to be (2/x^2)+3

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good job