Respuesta :

caylus
Hello,

[tex] \lim_{x \to 0}\ \dfrac{x^2-3*sin(x)}{x}\\\\ = \lim_{x \to 0}\ \dfrac{x^2}{x}-3* \lim_{x \to 0}\ \dfrac{sin(x)}{x}\\\\ =0-3*1=-3\\\\ [/tex]

Otras preguntas

good job