[tex]\bf 5x-\cfrac{y}{3}=13\quad \boxed{(\stackrel{x}{2}~,~\stackrel{y}{-9})}\implies 5(2)-\cfrac{-9}{3}=13\implies 10+3 = 13~ \checkmark
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5x-\cfrac{y}{3}=13\qquad \boxed{(\stackrel{x}{3}~,~\stackrel{y}{-6})}\implies 5(3)-\cfrac{-6}{3}=13\implies 15+2\ne 13[/tex]
