How would you solve 3x^2-12=0?

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08-09-2015
Mathematics

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How would you solve 3x^2-12=0?

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good job

AL2006 AL2006 · Answer 1 · 2015-09-08T23:29:31+02:00

   3x^2 - 12 = 0

Personally, I would divide each side by 3 x^2 - 4 = 0

Then I would add 4 to each side x^2     = 4

Then I would take the square root of each side: x = +4
   x = -4 .

Having found both solutions, I would relax with a cup of tea.