Respuesta :

iloveonedirection
[tex]2x^2 - x - 6 = 0[/tex]

[tex](2x - 3) (x + 2) = 0[/tex]

[tex]2x - 3 = 0[/tex]

[tex]2x = 3[/tex]

[tex]x = \frac{3}{2} [/tex]

[tex]x + 2 = 0[/tex]

[tex]x = -2[/tex]

[tex]x = \frac{3}{2} , 2[/tex]
konrad509
[tex]2x^2-x-6=0\\ 2x^2-4x+3x-6=0\\ 2x(x-2)+3(x-2)=0\\ (2x+3)(x-2)=0\\ x=-\frac{3}{2} \vee x=2[/tex]
good job