Respuesta :
[tex]\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount}\\\\
A=Pe^{rt}\qquad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$500\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &6
\end{cases}
\\\\\\
A=500e^{0.03\cdot 6}\implies A=500e^{0.18}\implies A\approx 598.6086815609[/tex]
