Good night from Canada! Let W be the width in meters Let L be the length in meters.
L*W=464464 L=2W-33 (2W-33)*W=464464 2W^2-33W=464464 2W^2-33W-464464=0 Use the quadratic formula to solve for the zeros x=-b√b²-4ac/2a Sub in b=-33 a=2 and c=-464464 and solve using position and negative values for the √b. We get: w=490.225 and w=473.725 Through simple algebra we can figure out that x=490.225 is more accurate when using it with the other equations and solving for the given area. L=2*490.225-33 L=947.45 947.45*490.225=464463.7
Therefore the length is 947.45m and the width is 490.225m.
