The schools basketball team lost 4 times as many as they won. They also tied 5 fewer games than they won. If they played 43 games how many did they loose?
Let x-------- > games won y--------- > lost games----------------- > y=4x (I) equation z------ > tied games--------------------- > z=x-5 (II) equation x+y+z=43 (III) equation
substitute (I) and (II) in (III) therefore x+(4x)+(x-5)=43--------------- >6x-5=43------------- > x=48/6 x=8 y=4x=4*8=32
