☾Let's solve this problem Step-By-Step!☽
☾Question you asked:
6(y+4)^2−5=49
☾Simplify both sides of the equation:
6y^2+48y+91=49
☾Subtract 49 from both sides:
6y^2+48y+91−49=49−49
6y^2+48y+42=0
☾Factor left side of equation:
6(y+1)(y+7)=0
☾Set factors equal to 0:
y+1=0 or y+7=0
☾Your answer is:
y=−1 or y=−7
☾I hope this helps!☽
