Answer:
Option A. [tex]4[/tex]
Step-by-step explanation:
we know that
The sum of a geometric series is equal to
[tex]Sum=a(\frac{1-r^{n}}{1-r})[/tex]
where
a is the first term
r is the common ratio
n is the number of terms
In this problem we have
[tex]a=2,r=0.5,n=16[/tex]
substitute the values
[tex]Sum=2(\frac{1-0.5^{16}}{1-0.5})=4[/tex]
