Answer:
the function that unites these two points is a constant line on y=-2
Step-by-step explanation:
P1=(-6,-2)
P2=(8,-2)
y=mx+b
In order to calculate m (the pendant):
m=[tex]\frac{-2-(-2)}{8-(-6)} \\[/tex]
m=0
Then, you need to replace y & x with the values of one of the points:
-2=0*(-6)+b
-2=b
Finally, replace m & b in y=mx+b:
y=-2
