Answer:
[tex]\frac{9+\sqrt{14}}{9+\sqrt{14}}[/tex]
Step-by-step explanation:
we have
[tex]\frac{5-\sqrt{7}}{9-\sqrt{14}}[/tex]
we know that
To rationalize the denominator, multiply by the conjugate of the denominator
so
[tex]\frac{5-\sqrt{7}}{9-\sqrt{14}}*\frac{9+\sqrt{14}}{9+\sqrt{14}}=\frac{(5-\sqrt{7})(9+\sqrt{14})}{9^{2}-14}\\ \\=\frac{(5-\sqrt{7})(9+\sqrt{14})}{67}[/tex]