Volume of cone:
[tex] V = \dfrac{1}{3}\pi r^2h [/tex]
Double the radius to 2r, and double the height to 2h.
Volume of new larger cone:
[tex] V = \dfrac{1}{3}\pi(2r)^2 \times 2h [/tex]
[tex] V = \dfrac{1}{3}\pi \times 4r^2 \times 2h [/tex]
[tex] V = \dfrac{1}{3}\pi \times 8r^2 h [/tex]
[tex] V = \dfrac{8}{3}\pi r^2 h [/tex]
Answer: Choice B)
