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  • 10-04-2018
  • Mathematics
contestada

Solve for x.

y=4+bx^2

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Аноним Аноним
  • 10-04-2018
[tex]y=4+bx^2[/tex]

[tex]bx^2 = y - 4[/tex]

[tex]x^2 = \dfrac{y-4}{b} [/tex]

[tex]x = \pm \sqrt{ \dfrac{y-4}{b} } [/tex]
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