Respuesta :

jgfm
[tex]x^{2}+4x = -8 \\\\ x^{2}+4x+8 = 0 \\\\ \Delta = b^{2}-4ac \\\\ \Delta = (4)^{2}-4 \cdot (1) \cdot (8) \\\\ \Delta = 16-32 \\\\ \Delta = -16[/tex]

There's no solution in the set of real numbers.

[tex]\boxed{S = \{ \ \ \}}[/tex]

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good job